What is the circumference 4x-x^2-y^2-6y-2>= 0 ?

The circumference 4x-x^2-y^2-6y-2>= 0 is C=2sqrt(11)pi

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circumference 4x-x^2-y^2-6y-2>= 0

circumference

4 x - x^{2} - y^{2} - 6 y - 2 \geq 0

C = 211 π

Solution steps

C = 2 π r

Find the radius

Radius given

4 x - x^{2} - y^{2} - 6 y - 2 \geq 0 : r = 11

C = 211 π

x^{2} + y^{2} + 2 x - 2 y = 0

x^{2} + y^{2} - 4 x + 6 y - 3 = 0

x^{2} + (y - 3)^{2} = 25

(x + 1)^{2} + (y + 8)^{2} = 7

X^{2} + Y^{2} = 4

What is the circumference 4x-x^2-y^2-6y-2>= 0 ?
The circumference 4x-x^2-y^2-6y-2>= 0 is C=2sqrt(11)pi