What is the circumference (x+1)^2+(y+8)^2=7 ?

The circumference (x+1)^2+(y+8)^2=7 is C=2sqrt(7)pi

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circumference (x+1)^2+(y+8)^2=7

circumference

(x + 1)^{2} + (y + 8)^{2} = 7

C = 27 π

Solution steps

C = 2 π r

Find the radius

Radius given

(x + 1)^{2} + (y + 8)^{2} = 7 : r = 7

C = 27 π

X^{2} + Y^{2} = 4

(x + 4)^{2} + (y - 3)^{2} = 16

x^{2} + y^{2} = \frac{25}{36}

(x + 1)^{2} + (y + 8)^{2} = 14

c i rc l e, f in d C i rc u m f ere n ce, g i v e n r = 10

What is the circumference (x+1)^2+(y+8)^2=7 ?
The circumference (x+1)^2+(y+8)^2=7 is C=2sqrt(7)pi