What is the circumference (x+4)^2+(y-3)^2=16 ?

The circumference (x+4)^2+(y-3)^2=16 is C=8pi

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circumference (x+4)^2+(y-3)^2=16

circumference

(x + 4)^{2} + (y - 3)^{2} = 16

C = 8 π

Solution steps

C = 2 π r

Find the radius

Radius given

(x + 4)^{2} + (y - 3)^{2} = 16 : r = 4

C = 2 π 4

Refine

C = 8 π

x^{2} + y^{2} = \frac{25}{36}

(x + 1)^{2} + (y + 8)^{2} = 14

c i rc l e, f in d C i rc u m f ere n ce, g i v e n r = 10

x^{2} + y^{2} + x + 3 y - 104 = 0

6 x^{2} + 6 y^{2} = 12 x + 12 y + 6

What is the circumference (x+4)^2+(y-3)^2=16 ?
The circumference (x+4)^2+(y-3)^2=16 is C=8pi