What is the circumference x^2+y^2+4x+12y-104=0 ?

The circumference x^2+y^2+4x+12y-104=0 is C=24pi

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circumference x^2+y^2+4x+12y-104=0

circumference

x^{2} + y^{2} + 4 x + 12 y - 104 = 0

C = 24 π

Solution steps

C = 2 π r

Find the radius

Radius given

x^{2} + y^{2} + 4 x + 12 y - 104 = 0 : r = 12

C = 2 π 12

Refine

C = 24 π

c i rc l e, f in d C i rc u m f ere n ce, g i v e n r = 3

(x - 5)^{2} + (y - 1)^{2} = 4

x^{2} + y^{2} \leq 1

x^{2} + y^{2} \leq 4

x^{2} + y^{2} + 6 x - 2 y - 15 = 0

What is the circumference x^2+y^2+4x+12y-104=0 ?
The circumference x^2+y^2+4x+12y-104=0 is C=24pi