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circumference x^2+y^2<= 4

Solution

circumference

x^{2} + y^{2} \leq 4

Solution

C = 4 π

Solution steps

C = 2 π r

Find the radius

Radius given

x^{2} + y^{2} \leq 4 : r = 2

C = 2 π 2

Refine

C = 4 π

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Frequently Asked Questions (FAQ)

What is the circumference x^2+y^2<= 4 ?
The circumference x^2+y^2<= 4 is C=4pi