What is the circumference 3x^2+3y^2+4y-7=0 ?

The circumference 3x^2+3y^2+4y-7=0 is C=(10pi)/3

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circumference 3x^2+3y^2+4y-7=0

circumference

3 x^{2} + 3 y^{2} + 4 y - 7 = 0

C = \frac{10 π}{3}

Solution steps

C = 2 π r

Find the radius

Radius given

3 x^{2} + 3 y^{2} + 4 y - 7 = 0 : r = \frac{5}{3}

C = 2 π \frac{5}{3}

Refine

C = \frac{10 π}{3}

x^{2} + y^{2} + 4 x + 12 y - 100 = 0

x^{2} + y^{2} - 6 x + 4 y + 8 = 0

x^{2} + (y - 7)^{2} = 36

(x - 5)^{2} + (y - 2)^{2} = 25

x^{2} + (y - 1)^{2} = 4

What is the circumference 3x^2+3y^2+4y-7=0 ?
The circumference 3x^2+3y^2+4y-7=0 is C=(10pi)/3