What is the circumference x^2+y^2+4x-6y+12=0 ?

The circumference x^2+y^2+4x-6y+12=0 is C=2pi

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circumference x^2+y^2+4x-6y+12=0

circumference

x^{2} + y^{2} + 4 x - 6 y + 12 = 0

C = 2 π

Solution steps

C = 2 π r

Find the radius

Radius given

x^{2} + y^{2} + 4 x - 6 y + 12 = 0 : r = 1

C = 2 π 1

Refine

C = 2 π

(x - 2)^{2} + (y + 6)^{2} = 16

x^{2} - 12 x + y^{2} - 8 y = 6

x^{2} + y^{2} + 10 x - 4 y - 7 = 0

x^{2} + y^{2} - 10 x - 10 y + 25 = 0

x^{2} + y^{2} + 4 x - 2 y = - 1

What is the circumference x^2+y^2+4x-6y+12=0 ?
The circumference x^2+y^2+4x-6y+12=0 is C=2pi