What is the radius x^2+y^2-14x-12y+59=0 ?

The radius x^2+y^2-14x-12y+59=0 is r=sqrt(26)

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radius x^2+y^2-14x-12y+59=0

radius

x^{2} + y^{2} - 14 x - 12 y + 59 = 0

r = 26

Solution steps

x^{2} + y^{2} - 14 x - 12 y + 59 = 0

Rewrite

x^{2} + y^{2} - 14 x - 12 y + 59 = 0

in the form of the standard circle equation

(x - 7)^{2} + (y - 6)^{2} = (26)^{2}

Therefore the circle properties are:

(a, b) = (7, 6), r = 26

And the radius is:

r = 26

(x + 5)^{2} + (y - 2)^{2} = 25

x^{2} + (y - 4)^{2} = 1

x^{2} + (y - 4)^{2} = 4

x^{2} + y^{2} + 9 x - 9 y - 17 = 0

x^{2} + y^{2} + 6 x + 8 y + 24 = 0

What is the radius x^2+y^2-14x-12y+59=0 ?
The radius x^2+y^2-14x-12y+59=0 is r=sqrt(26)