What is the radius (x+2)^2+(y-4)^2=25 ?

The radius (x+2)^2+(y-4)^2=25 is r=5

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radius (x+2)^2+(y-4)^2=25

radius

(x + 2)^{2} + (y - 4)^{2} = 25

r = 5

Solution steps

(x + 2)^{2} + (y - 4)^{2} = 25

Rewrite

(x + 2)^{2} + (y - 4)^{2} = 25

in the form of the standard circle equation

(x - (- 2))^{2} + (y - 4)^{2} = 5^{2}

Therefore the circle properties are:

(a, b) = (- 2, 4), r = 5

And the radius is:

r = 5

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