What is the radius x^2+6x+y^2-2y-15=0 ?

The radius x^2+6x+y^2-2y-15=0 is r=5

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radius x^2+6x+y^2-2y-15=0

radius

x^{2} + 6 x + y^{2} - 2 y - 15 = 0

r = 5

Solution steps

x^{2} + 6 x + y^{2} - 2 y - 15 = 0

Rewrite

x^{2} + 6 x + y^{2} - 2 y - 15 = 0

in the form of the standard circle equation

(x - (- 3))^{2} + (y - 1)^{2} = 5^{2}

Therefore the circle properties are:

(a, b) = (- 3, 1), r = 5

And the radius is:

r = 5

x^{2} + y^{2} - 8 x + 10 y - 8 = 0

X^{2} + Y^{2} = 49

x^{2} + (y - 2)^{2} = 36

x^{2} + y^{2} \leq 25

(x + 6)^{2} + (y - 7)^{2} = 81