What is the radius x^2+y^2-4x+8y+11=0 ?

The radius x^2+y^2-4x+8y+11=0 is r=3

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radius x^2+y^2-4x+8y+11=0

radius

x^{2} + y^{2} - 4 x + 8 y + 11 = 0

r = 3

Solution steps

x^{2} + y^{2} - 4 x + 8 y + 11 = 0

Rewrite

x^{2} + y^{2} - 4 x + 8 y + 11 = 0

in the form of the standard circle equation

(x - 2)^{2} + (y - (- 4))^{2} = 3^{2}

Therefore the circle properties are:

(a, b) = (2, - 4), r = 3

And the radius is:

r = 3

4 x^{2} + 4 y^{2} - x + 2 y - 11 = 0

(x + 4)^{2} + (y - 3)^{2} = 4

x^{2} + y^{2} + 2 y - 15 = 0

x^{2} + y^{2} = 144

(x - \frac{6}{5})^{2} + (y + \frac{1}{3})^{2} = \frac{49}{9}