What is the radius (x-6/5)^2+(y+1/3)^2= 49/9 ?

The radius (x-6/5)^2+(y+1/3)^2= 49/9 is r= 7/3

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radius (x-6/5)^2+(y+1/3)^2= 49/9

radius

(x - \frac{6}{5})^{2} + (y + \frac{1}{3})^{2} = \frac{49}{9}

r = \frac{7}{3}

Solution steps

(x - \frac{6}{5})^{2} + (y + \frac{1}{3})^{2} = \frac{49}{9}

Rewrite

(x - \frac{6}{5})^{2} + (y + \frac{1}{3})^{2} = \frac{49}{9}

in the form of the standard circle equation

(x - \frac{6}{5})^{2} + (y - (- \frac{1}{3}))^{2} = (\frac{7}{3})^{2}

Therefore the circle properties are:

(a, b) = (\frac{6}{5}, - \frac{1}{3}), r = \frac{7}{3}

And the radius is:

r = \frac{7}{3}

x^{2} + y^{2} = 4

x^{2} + y^{2} + 8 x - 6 y + 24 = 0

2 x^{2} + 2 y^{2} + 16 x - 6 y - 18 = 0

(x - (- 5))^{2} + (y - 7)^{2} = 3^{2}

(x + 6)^{2} + (y - 1)^{2} = 16

What is the radius (x-6/5)^2+(y+1/3)^2= 49/9 ?
The radius (x-6/5)^2+(y+1/3)^2= 49/9 is r= 7/3