What is the radius x^2+y^2-2x-8y-19=0(1.5)6 ?

The radius x^2+y^2-2x-8y-19=0(1.5)6 is r=6

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

radius x^2+y^2-2x-8y-19=0(1.5)6

radius

x^{2} + y^{2} - 2 x - 8 y - 19 = 0 (1.5) 6

r = 6

Solution steps

x^{2} + y^{2} - 2 x - 8 y - 19 = 0 \cdot 1.5 \cdot 6

Rewrite

x^{2} + y^{2} - 2 x - 8 y - 19 = 01.56

in the form of the standard circle equation

(x - 1)^{2} + (y - 4)^{2} = 6^{2}

Therefore the circle properties are:

(a, b) = (1, 4), r = 6

And the radius is:

r = 6

x^{2} + y^{2} - 10 x + 12 y = 195

4 (x - 5)^{2} + 4 y^{2} = 4

x^{2} + 2 x + y^{2} - 2 y = - 1

(x - 9)^{2} + (y - 4)^{2} = 25

x^{2} + y^{2} - 2 x + 2 y - 7 = 0

What is the radius x^2+y^2-2x-8y-19=0(1.5)6 ?
The radius x^2+y^2-2x-8y-19=0(1.5)6 is r=6