What is the radius x^2+y^2-10x+7y-29=0 ?

The radius x^2+y^2-10x+7y-29=0 is r=(sqrt(265))/2

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radius x^2+y^2-10x+7y-29=0

radius

x^{2} + y^{2} - 10 x + 7 y - 29 = 0

r = \frac{265}{2}

Solution steps

x^{2} + y^{2} - 10 x + 7 y - 29 = 0

Rewrite

x^{2} + y^{2} - 10 x + 7 y - 29 = 0

in the form of the standard circle equation

(x - 5)^{2} + (y - (- \frac{7}{2}))^{2} = (\frac{265}{2})^{2}

Therefore the circle properties are:

(a, b) = (5, - \frac{7}{2}), r = \frac{265}{2}

And the radius is:

r = \frac{265}{2}

9 x^{2} + 54 x + 9 y^{2} - 6 y + 28 = 0

x^{2} + y^{2} + 6 x + 5 y = - \frac{45}{4}

x^{2} + y^{2} - 8 x + 18 y + 16 = 0

(x - 1)^{2} + (y + 4)^{2} = 16

x^{2} + y^{2} + 2 x - 4 y - 15 = 0

What is the radius x^2+y^2-10x+7y-29=0 ?
The radius x^2+y^2-10x+7y-29=0 is r=(sqrt(265))/2