What is the radius x^2+y^2-13=0 ?

The radius x^2+y^2-13=0 is r=sqrt(13)

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radius x^2+y^2-13=0

radius

x^{2} + y^{2} - 13 = 0

r = 13

Solution steps

x^{2} + y^{2} - 13 = 0

Rewrite

x^{2} + y^{2} - 13 = 0

in the form of the standard circle equation

(x - 0)^{2} + (y - 0)^{2} = (13)^{2}

Therefore the circle properties are:

(a, b) = (0, 0), r = 13

And the radius is:

r = 13

(x + \frac{7}{2})^{2} + (y - \frac{1}{2})^{2} = 5

4 x^{2} + 4 y^{2} - 3 x + 5 y - 5 = 0

\frac{( x + 7 ) ^{2}}{16} + \frac{( y + 5 ) ^{2}}{16} = 1

x^{2} + y^{2} + 14 x - 18 y + 81 = 0

x^{2} + y^{2} - 2 x - 16 y + 40 = 0