What is the radius x^2+y^2-6x+10y+9=0 ?

The radius x^2+y^2-6x+10y+9=0 is r=5

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radius x^2+y^2-6x+10y+9=0

radius

x^{2} + y^{2} - 6 x + 10 y + 9 = 0

r = 5

Solution steps

x^{2} + y^{2} - 6 x + 10 y + 9 = 0

Rewrite

x^{2} + y^{2} - 6 x + 10 y + 9 = 0

in the form of the standard circle equation

(x - 3)^{2} + (y - (- 5))^{2} = 5^{2}

Therefore the circle properties are:

(a, b) = (3, - 5), r = 5

And the radius is:

r = 5

x^{2} + y^{2} + 12 y + 32 = 0

2 x^{2} + 2 y^{2} + 10 x - 6 y - 55 = 0

x^{2} - 6 x + 9 + y^{2} - 4 y + 4 = 16

x^{2} + y^{2} - 4 x + 6 y - 3 = 0

x^{2} + y^{2} + 6 x - 2 y - 15 = 0