What is the radius (x+8/3)^2+y^2=1 ?

The radius (x+8/3)^2+y^2=1 is r=1

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radius (x+8/3)^2+y^2=1

radius

(x + \frac{8}{3})^{2} + y^{2} = 1

r = 1

Solution steps

(x + \frac{8}{3})^{2} + y^{2} = 1

Rewrite

(x + \frac{8}{3})^{2} + y^{2} = 1

in the form of the standard circle equation

(x - (- \frac{8}{3}))^{2} + (y - 0)^{2} = 1^{2}

Therefore the circle properties are:

(a, b) = (- \frac{8}{3}, 0), r = 1

And the radius is:

r = 1

x^{2} - 6 x + y^{2} + 8 y = 0

x^{2} + y^{2} = 3 x + 4 y

x^{2} + y^{2} - 10 x + 10 y + 49 = 0

x^{2} + (y - 1)^{2} = 64

x^{2} + (y - 1)^{2} = 16