What is the radius (y+8)^2+(x+2)^2=72 ?

The radius (y+8)^2+(x+2)^2=72 is r=sqrt(72)

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radius (y+8)^2+(x+2)^2=72

radius

(y + 8)^{2} + (x + 2)^{2} = 72

r = 72

Solution steps

(y + 8)^{2} + (x + 2)^{2} = 72

Rewrite

(y + 8)^{2} + (x + 2)^{2} = 72

in the form of the standard circle equation

(x - (- 2))^{2} + (y - (- 8))^{2} = (72)^{2}

Therefore the circle properties are:

(a, b) = (- 2, - 8), r = 72

And the radius is:

r = 72

5 x^{2} - 20 x + 5 y^{2} + 30 y - 11 = 0

x^{2} + y^{2} - 6 x + 10 y + 9 = 0

x^{2} + y^{2} + 12 y + 32 = 0

2 x^{2} + 2 y^{2} + 10 x - 6 y - 55 = 0

x^{2} - 6 x + 9 + y^{2} - 4 y + 4 = 16

What is the radius (y+8)^2+(x+2)^2=72 ?
The radius (y+8)^2+(x+2)^2=72 is r=sqrt(72)