What is the radius (x-3)^2+(y+8)^2=35 ?

The radius (x-3)^2+(y+8)^2=35 is r=sqrt(35)

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radius (x-3)^2+(y+8)^2=35

radius

(x - 3)^{2} + (y + 8)^{2} = 35

r = 35

Solution steps

(x - 3)^{2} + (y + 8)^{2} = 35

Rewrite

(x - 3)^{2} + (y + 8)^{2} = 35

in the form of the standard circle equation

(x - 3)^{2} + (y - (- 8))^{2} = (35)^{2}

Therefore the circle properties are:

(a, b) = (3, - 8), r = 35

And the radius is:

r = 35

(y + 8)^{2} + (x + 2)^{2} = 72

5 x^{2} - 20 x + 5 y^{2} + 30 y - 11 = 0

x^{2} + y^{2} - 6 x + 10 y + 9 = 0

x^{2} + y^{2} + 12 y + 32 = 0

2 x^{2} + 2 y^{2} + 10 x - 6 y - 55 = 0

What is the radius (x-3)^2+(y+8)^2=35 ?
The radius (x-3)^2+(y+8)^2=35 is r=sqrt(35)