What is the radius x^2+y^2+10x-18y+70=0 ?

The radius x^2+y^2+10x-18y+70=0 is r=6

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radius x^2+y^2+10x-18y+70=0

radius

x^{2} + y^{2} + 10 x - 18 y + 70 = 0

r = 6

Solution steps

x^{2} + y^{2} + 10 x - 18 y + 70 = 0

Rewrite

x^{2} + y^{2} + 10 x - 18 y + 70 = 0

in the form of the standard circle equation

(x - (- 5))^{2} + (y - 9)^{2} = 6^{2}

Therefore the circle properties are:

(a, b) = (- 5, 9), r = 6

And the radius is:

r = 6

(x - 2)^{2} + y^{2} = 25

x^{2} + y^{2} - 4 x = 5

x^{2} + y^{2} + 2 x - 10 y - 10 = 0

(x + 5)^{2} + (y - 7)^{2} = 289

x^{2} + y^{2} + 2 x - 6 y = 0

What is the radius x^2+y^2+10x-18y+70=0 ?
The radius x^2+y^2+10x-18y+70=0 is r=6