What is the radius x^2-2x+y^2+4y=11 ?

The radius x^2-2x+y^2+4y=11 is r=4

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radius x^2-2x+y^2+4y=11

radius

x^{2} - 2 x + y^{2} + 4 y = 11

r = 4

Solution steps

x^{2} - 2 x + y^{2} + 4 y = 11

Rewrite

x^{2} - 2 x + y^{2} + 4 y = 11

in the form of the standard circle equation

(x - 1)^{2} + (y - (- 2))^{2} = 4^{2}

Therefore the circle properties are:

(a, b) = (1, - 2), r = 4

And the radius is:

r = 4

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