What is the radius x^2+y^2-4x+2y-11=0 ?

The radius x^2+y^2-4x+2y-11=0 is r=4

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radius x^2+y^2-4x+2y-11=0

radius

x^{2} + y^{2} - 4 x + 2 y - 11 = 0

r = 4

Solution steps

x^{2} + y^{2} - 4 x + 2 y - 11 = 0

Rewrite

x^{2} + y^{2} - 4 x + 2 y - 11 = 0

in the form of the standard circle equation

(x - 2)^{2} + (y - (- 1))^{2} = 4^{2}

Therefore the circle properties are:

(a, b) = (2, - 1), r = 4

And the radius is:

r = 4

x^{2} + y^{2} - 6 x + 4 y = 7

x^{2} + y^{2} - 6 = 0

x^{2} + y^{2} - 14 x + 6 y + 49 = 0

(x + 4)^{2} + (y - 6)^{2} = 18

2 (x - 2)^{2} + 2 y^{2} = 2