What is the radius 3(x-2)^2+3y^2=3 ?

The radius 3(x-2)^2+3y^2=3 is r=1

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radius 3(x-2)^2+3y^2=3

radius

3 (x - 2)^{2} + 3 y^{2} = 3

r = 1

Solution steps

3 (x - 2)^{2} + 3 y^{2} = 3

Rewrite

3 (x - 2)^{2} + 3 y^{2} = 3

in the form of the standard circle equation

(x - 2)^{2} + (y - 0)^{2} = 1^{2}

Therefore the circle properties are:

(a, b) = (2, 0), r = 1

And the radius is:

r = 1

x^{2} + y^{2} - 14 x + 2 y + 41 = 0

x^{2} + 2 x + y^{2} + 4 y = 20

x^{2} + 10 x + y^{2} - 16 y - 11 = 0

x^{2} - 6 x + y^{2} + 8 y - 24 = 0

x^{2} + 24 x + y^{2} + 10 y = - 160