Solution

center

Solution

Solution steps
Rewrite in the form of the standard circle equation
Therefore the circle properties are:
And the center is:

Popular Examples

center 2x^2+32x+2y^2-12=-128center center (x-3)^2+(y+3)^2=8center center x^2+y^2-4x-6y-12=0center center x^2-4x+y^2+8y=-4center center x^2+y^2-10x-12y+45=0center

Frequently Asked Questions (FAQ)

  • What is the center x^2+y^2+4x-2y+1=0 ?

    The center x^2+y^2+4x-2y+1=0 is (-2,1)