What is the center x^2+y^2-10x-12y+45=0 ?

The center x^2+y^2-10x-12y+45=0 is (5,6)

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center x^2+y^2-10x-12y+45=0

center

x^{2} + y^{2} - 10 x - 12 y + 45 = 0

(5, 6)

Solution steps

x^{2} + y^{2} - 10 x - 12 y + 45 = 0

Rewrite

x^{2} + y^{2} - 10 x - 12 y + 45 = 0

in the form of the standard circle equation

(x - 5)^{2} + (y - 6)^{2} = 4^{2}

Therefore the circle properties are:

(a, b) = (5, 6), r = 4

And the center is:

(5, 6)

x^{2} + y^{2} - 8 x + 2 y + 13 = 0

(x + 4)^{2} + (y - (- 1))^{2} = 12

3 x^{2} + 3 y^{2} - 27 x - 9 y - 24 = 0

2 x^{2} + 2 y^{2} - 16 x + 4 y - 16 = 0

(x - 1)^{2} + (y + 3)^{2} = 16

What is the center x^2+y^2-10x-12y+45=0 ?
The center x^2+y^2-10x-12y+45=0 is (5,6)