What is (x+10/3)^2+y^2=4 ?

The solution to (x+10/3)^2+y^2=4 is Circle with (a,b)=(-10/3 ,0),r=2

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(x+10/3)^2+y^2=4

(x + \frac{10}{3})^{2} + y^{2} = 4

(a, b) = (- \frac{10}{3}, 0), r = 2

Solution steps

(x + \frac{10}{3})^{2} + y^{2} = 4

Rewrite

(x + \frac{10}{3})^{2} + y^{2} = 4

in the form of the standard circle equation

(x - (- \frac{10}{3}))^{2} + (y - 0)^{2} = 2^{2}

Therefore the circle properties are:

(a, b) = (- \frac{10}{3}, 0), r = 2

x^{2} + y^{2} + 5 x - 7 y - 18 = 0

x^{2} + (y - 10)^{2} = 225

2 x^{2} - 6 x + 2 y^{2} + 2 y - 45 = 0

(x + 2)^{2} + (y - 5)^{2} = 1

(x - 1)^{2} + (y + 3)^{2} = 4^{2}

What is (x+10/3)^2+y^2=4 ?
The solution to (x+10/3)^2+y^2=4 is Circle with (a,b)=(-10/3 ,0),r=2