What is 2x^2-6x+2y^2+2y-45=0 ?

The solution to 2x^2-6x+2y^2+2y-45=0 is Circle with (a,b)=(3/2 ,-1/2),r=5

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2x^2-6x+2y^2+2y-45=0

2 x^{2} - 6 x + 2 y^{2} + 2 y - 45 = 0

(a, b) = (\frac{3}{2}, - \frac{1}{2}), r = 5

Solution steps

2 x^{2} - 6 x + 2 y^{2} + 2 y - 45 = 0

Rewrite

2 x^{2} - 6 x + 2 y^{2} + 2 y - 45 = 0

in the form of the standard circle equation

(x - \frac{3}{2})^{2} + (y - (- \frac{1}{2}))^{2} = 5^{2}

Therefore the circle properties are:

(a, b) = (\frac{3}{2}, - \frac{1}{2}), r = 5

(x + 2)^{2} + (y - 5)^{2} = 1

(x - 1)^{2} + (y + 3)^{2} = 4^{2}

(x + 1)^{2} + (y - 1)^{2} = 6^{2}

x^{2} + (y + 9)^{2} = 81

(x + 2)^{2} - 4 + (y - 1)^{2} + 1 = 0

What is 2x^2-6x+2y^2+2y-45=0 ?
The solution to 2x^2-6x+2y^2+2y-45=0 is Circle with (a,b)=(3/2 ,-1/2),r=5