What is (x-6)^2+y^2=1 ?

The solution to (x-6)^2+y^2=1 is Circle with (a,b)=(6,0),r=1

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(x-6)^2+y^2=1

(x - 6)^{2} + y^{2} = 1

(a, b) = (6, 0), r = 1

Solution steps

(x - 6)^{2} + y^{2} = 1

Rewrite

(x - 6)^{2} + y^{2} = 1

in the form of the standard circle equation

(x - 6)^{2} + (y - 0)^{2} = 1^{2}

Therefore the circle properties are:

(a, b) = (6, 0), r = 1

(x - 7)^{2} + (y + 3)^{2} = 9

(x + 0.738)^{2} + (y + 1.119)^{2} = 6.99 6^{2}

x^{2} + y^{2} + 12 x + 9 y - 18 = 0

(x + 14)^{2} + y^{2} = 144

x^{2} + y^{2} - 8 x - 4 y + 5 = 0

What is (x-6)^2+y^2=1 ?
The solution to (x-6)^2+y^2=1 is Circle with (a,b)=(6,0),r=1