What is x^2+y^2-6x-12y+36=0 ?

The solution to x^2+y^2-6x-12y+36=0 is Circle with (a,b)=(3,6),r=3

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x^2+y^2-6x-12y+36=0

x^{2} + y^{2} - 6 x - 12 y + 36 = 0

(a, b) = (3, 6), r = 3

Solution steps

x^{2} + y^{2} - 6 x - 12 y + 36 = 0

Rewrite

x^{2} + y^{2} - 6 x - 12 y + 36 = 0

in the form of the standard circle equation

(x - 3)^{2} + (y - 6)^{2} = 3^{2}

Therefore the circle properties are:

(a, b) = (3, 6), r = 3

2 x^{2} + 2 y^{2} + 15 x + 15 y - 15 = 0

(x - 2)^{(2)} + (y + 1)^{(2)} \geq 4

(x - 2)^{2} + (y - 6)^{2} = 16

(x - 3)^{2} + (y - 5)^{2} = 6^{2}

(x + \frac{54}{13})^{2} + (y - \frac{123}{26})^{2} = \frac{5165}{52}

What is x^2+y^2-6x-12y+36=0 ?
The solution to x^2+y^2-6x-12y+36=0 is Circle with (a,b)=(3,6),r=3