What is (x-37.5)^2+(y+2.5)^2=1^2 ?

The solution to (x-37.5)^2+(y+2.5)^2=1^2 is Circle with (a,b)=(37.5,-2.5),r=1

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(x-37.5)^2+(y+2.5)^2=1^2

(x - 37.5)^{2} + (y + 2.5)^{2} = 1^{2}

(a, b) = (37.5, - 2.5), r = 1

Solution steps

(x - 37.5)^{2} + (y + 2.5)^{2} = 1^{2}

Rewrite

(x - 37.5)^{2} + (y + 2.5)^{2} = 1^{2}

in the form of the standard circle equation

(x - 37.5)^{2} + (y - (- 2.5))^{2} = 1^{2}

Therefore the circle properties are:

(a, b) = (37.5, - 2.5), r = 1

(y - 2)^{2} + (x - 8)^{2} = 64

x^{2} + y^{2} - 18 x + 4 y + 60 = 0

x^{2} + y^{2} - 10 x - 16 y - 9 = 0

x^{2} + y^{2} = 17 - 16

x^{2} + y^{2} - 10 x + 20 y + 100 = 0

What is (x-37.5)^2+(y+2.5)^2=1^2 ?
The solution to (x-37.5)^2+(y+2.5)^2=1^2 is Circle with (a,b)=(37.5,-2.5),r=1