What is (2+y)^2+(2+x)^2=6^2 ?

The solution to (2+y)^2+(2+x)^2=6^2 is Circle with (a,b)=(-2,-2),r=6

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(2+y)^2+(2+x)^2=6^2

(2 + y)^{2} + (2 + x)^{2} = 6^{2}

(a, b) = (- 2, - 2), r = 6

Solution steps

(2 + y)^{2} + (2 + x)^{2} = 6^{2}

Rewrite

(2 + y)^{2} + (2 + x)^{2} = 6^{2}

in the form of the standard circle equation

(x - (- 2))^{2} + (y - (- 2))^{2} = 6^{2}

Therefore the circle properties are:

(a, b) = (- 2, - 2), r = 6

x^{2} + (y + 1)^{2} = 10

x^{2} + (y + 1)^{2} = 11

(x - 3)^{2} + (y - 5)^{2} + (x + 4)^{2} + (y - 2)^{2} = 30

x^{2} + y^{2} - 5 y - 4 y = 46

(x - 2)^{2} + (y + 1)^{2} - 9 = 0

What is (2+y)^2+(2+x)^2=6^2 ?
The solution to (2+y)^2+(2+x)^2=6^2 is Circle with (a,b)=(-2,-2),r=6