What is (x-3)^2+(y-5)^2+(x+4)^2+(y-2)^2=30 ?

The solution to (x-3)^2+(y-5)^2+(x+4)^2+(y-2)^2=30 is Circle with (a,b)=(-1/2 , 7/2),r=sqrt(1/2)

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(x-3)^2+(y-5)^2+(x+4)^2+(y-2)^2=30

(x - 3)^{2} + (y - 5)^{2} + (x + 4)^{2} + (y - 2)^{2} = 30

(a, b) = (- \frac{1}{2}, \frac{7}{2}), r = \frac{1}{2}

Solution steps

(x - 3)^{2} + (y - 5)^{2} + (x + 4)^{2} + (y - 2)^{2} = 30

Rewrite

(x - 3)^{2} + (y - 5)^{2} + (x + 4)^{2} + (y - 2)^{2} = 30

in the form of the standard circle equation

(x - (- \frac{1}{2}))^{2} + (y - \frac{7}{2})^{2} = (\frac{1}{2})^{2}

Therefore the circle properties are:

(a, b) = (- \frac{1}{2}, \frac{7}{2}), r = \frac{1}{2}

x^{2} + y^{2} - 5 y - 4 y = 46

(x - 2)^{2} + (y + 1)^{2} - 9 = 0

(x - 1)^{2} + (y - 1)^{2} = 20

(x - 1)^{2} + (y - 1)^{2} = 16

(x - 2)^{2} + (y + 2)^{2} = 9

What is (x-3)^2+(y-5)^2+(x+4)^2+(y-2)^2=30 ?
The solution to (x-3)^2+(y-5)^2+(x+4)^2+(y-2)^2=30 is Circle with (a,b)=(-1/2 , 7/2),r=sqrt(1/2)