What is x^2+y^2-5y-4y=46 ?

The solution to x^2+y^2-5y-4y=46 is Circle with (a,b)=(0, 9/2),r=(sqrt(265))/2

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x^2+y^2-5y-4y=46

x^{2} + y^{2} - 5 y - 4 y = 46

(a, b) = (0, \frac{9}{2}), r = \frac{265}{2}

Solution steps

x^{2} + y^{2} - 5 y - 4 y = 46

Rewrite

x^{2} + y^{2} - 5 y - 4 y = 46

in the form of the standard circle equation

(x - 0)^{2} + (y - \frac{9}{2})^{2} = (\frac{265}{2})^{2}

Therefore the circle properties are:

(a, b) = (0, \frac{9}{2}), r = \frac{265}{2}

(x - 2)^{2} + (y + 1)^{2} - 9 = 0

(x - 1)^{2} + (y - 1)^{2} = 20

(x - 1)^{2} + (y - 1)^{2} = 16

(x - 2)^{2} + (y + 2)^{2} = 9

(x + 1)^{2} + (y - 2)^{2} = 2

What is x^2+y^2-5y-4y=46 ?
The solution to x^2+y^2-5y-4y=46 is Circle with (a,b)=(0, 9/2),r=(sqrt(265))/2