What is 5x^2+5y^2-9x-19y-26=0 ?

The solution to 5x^2+5y^2-9x-19y-26=0 is Circle with (a,b)=(9/10 , 19/10),r=(sqrt(481))/(5sqrt(2))

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5x^2+5y^2-9x-19y-26=0

5 x^{2} + 5 y^{2} - 9 x - 19 y - 26 = 0

(a, b) = (\frac{9}{10}, \frac{19}{10}), r = \frac{481}{5 2}

Solution steps

5 x^{2} + 5 y^{2} - 9 x - 19 y - 26 = 0

Rewrite

5 x^{2} + 5 y^{2} - 9 x - 19 y - 26 = 0

in the form of the standard circle equation

(x - \frac{9}{10})^{2} + (y - \frac{19}{10})^{2} = (\frac{481}{5 2})^{2}

Therefore the circle properties are:

(a, b) = (\frac{9}{10}, \frac{19}{10}), r = \frac{481}{5 2}

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What is 5x^2+5y^2-9x-19y-26=0 ?
The solution to 5x^2+5y^2-9x-19y-26=0 is Circle with (a,b)=(9/10 , 19/10),r=(sqrt(481))/(5sqrt(2))