What is 2x+2y=x^2+y^2 ?

The solution to 2x+2y=x^2+y^2 is Circle with (a,b)=(1,1),r=sqrt(2)

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2x+2y=x^2+y^2

2 x + 2 y = x^{2} + y^{2}

(a, b) = (1, 1), r = 2

Solution steps

2 x + 2 y = x^{2} + y^{2}

Rewrite

2 x + 2 y = x^{2} + y^{2}

in the form of the standard circle equation

(x - 1)^{2} + (y - 1)^{2} = (2)^{2}

Therefore the circle properties are:

(a, b) = (1, 1), r = 2

13 x^{2} + 13 y^{2} - 19 x + 5 y - 132 = 0

x^{2} + y^{2} - 10 x + 2 y + 1 = 0

x^{2} + y^{2} - 4 x + 2 y - 8 = 0

0.5 9^{2} = (x - (- 0.02))^{2} + (y - 0.78)^{2}

(x + \frac{23}{5})^{2} + (y - \frac{2}{5})^{2} = \frac{373}{5}

What is 2x+2y=x^2+y^2 ?
The solution to 2x+2y=x^2+y^2 is Circle with (a,b)=(1,1),r=sqrt(2)