What is (x-(-6))^2+(y-9)^2=10^2 ?

The solution to (x-(-6))^2+(y-9)^2=10^2 is Circle with (a,b)=(-6,9),r=10

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(x-(-6))^2+(y-9)^2=10^2

(x - (- 6))^{2} + (y - 9)^{2} = 1 0^{2}

(a, b) = (- 6, 9), r = 10

Solution steps

(x - (- 6))^{2} + (y - 9)^{2} = 1 0^{2}

Rewrite

(x - (- 6))^{2} + (y - 9)^{2} = 1 0^{2}

in the form of the standard circle equation

(x - (- 6))^{2} + (y - 9)^{2} = 1 0^{2}

Therefore the circle properties are:

(a, b) = (- 6, 9), r = 10

x^{2} - 2 y + y^{2} = 12

8 = x^{2} + y^{2}

x^{2} + y^{2} + 2 x - 2 y - 8 = 0

x^{2} + y^{2} - 12 x - 16 y + 36 = 0

\frac{1}{4} x^{2} - \frac{5}{4} x + \frac{1}{4} y^{2} + \frac{9}{4} y = 3

What is (x-(-6))^2+(y-9)^2=10^2 ?
The solution to (x-(-6))^2+(y-9)^2=10^2 is Circle with (a,b)=(-6,9),r=10