What is (y+5)^2=100-(x+2)^2 ?

The solution to (y+5)^2=100-(x+2)^2 is Circle with (a,b)=(-2,-5),r=10

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(y+5)^2=100-(x+2)^2

(y + 5)^{2} = 100 - (x + 2)^{2}

(a, b) = (- 2, - 5), r = 10

Solution steps

(y + 5)^{2} = 100 - (x + 2)^{2}

Rewrite

(y + 5)^{2} = 100 - (x + 2)^{2}

in the form of the standard circle equation

(x - (- 2))^{2} + (y - (- 5))^{2} = 1 0^{2}

Therefore the circle properties are:

(a, b) = (- 2, - 5), r = 10

x^{2} + y^{2} + 16 x + 14 y + 104 = 0

(x - (- 6))^{2} + (y - 9)^{2} = 1 0^{2}

x^{2} - 2 y + y^{2} = 12

8 = x^{2} + y^{2}

x^{2} + y^{2} + 2 x - 2 y - 8 = 0

What is (y+5)^2=100-(x+2)^2 ?
The solution to (y+5)^2=100-(x+2)^2 is Circle with (a,b)=(-2,-5),r=10