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Popular >

8=x^2+y^2

Solution

8 = x^{2} + y^{2}

Solution

(a, b) = (0, 0), r = 22

Solution steps

8 = x^{2} + y^{2}

Rewrite

8 = x^{2} + y^{2}

in the form of the standard circle equation

(x - 0)^{2} + (y - 0)^{2} = (22)^{2}

Therefore the circle properties are:

(a, b) = (0, 0), r = 22

Popular Examples

x^2+y^2+2x-2y-8=0

x^{2} + y^{2} + 2 x - 2 y - 8 = 0

x^2+y^2-12x-16y+36=0

x^{2} + y^{2} - 12 x - 16 y + 36 = 0

1/4 x^2-5/4 x+1/4 y^2+9/4 y=3

\frac{1}{4} x^{2} - \frac{5}{4} x + \frac{1}{4} y^{2} + \frac{9}{4} y = 3

(x+4)^2+(y+4)^2=16^2

(x + 4)^{2} + (y + 4)^{2} = 1 6^{2}

x^{2} + y^{2} = 3 x + y - 2

Frequently Asked Questions (FAQ)

What is 8=x^2+y^2 ?
The solution to 8=x^2+y^2 is Circle with (a,b)=(0,0),r=2sqrt(2)