What is 16=(x)^2+(y)^2 ?

The solution to 16=(x)^2+(y)^2 is Circle with (a,b)=(0,0),r=4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

16=(x)^2+(y)^2

16 = (x)^{2} + (y)^{2}

(a, b) = (0, 0), r = 4

Solution steps

16 = x^{2} + y^{2}

Rewrite

16 = x^{2} + y^{2}

in the form of the standard circle equation

(x - 0)^{2} + (y - 0)^{2} = 4^{2}

Therefore the circle properties are:

(a, b) = (0, 0), r = 4

2 x^{2} + 2 y^{2} - 3 x + 5 y - 4 = 0

(x - 3)^{2} + (y - 5)^{2} = 25

x^{2} + y^{2} + 10 x - 16 y + 64 = 0

2 (x^{2} - 3) + 2 (y^{2} - 1) = 45

(x + 2)^{2} + (y - 1.5)^{2} = (2.75 i)

What is 16=(x)^2+(y)^2 ?
The solution to 16=(x)^2+(y)^2 is Circle with (a,b)=(0,0),r=4