What is x^2+y^2=sqrt(10) ?

The solution to x^2+y^2=sqrt(10) is Circle with (a,b)=(0,0),r=sqrt(\sqrt{10)}

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x^2+y^2=sqrt(10)

x^{2} + y^{2} = 10

(a, b) = (0, 0), r = 10

Solution steps

x^{2} + y^{2} = 10

Rewrite

x^{2} + y^{2} = 10

in the form of the standard circle equation

(x - 0)^{2} + (y - 0)^{2} = (10)^{2}

Therefore the circle properties are:

(a, b) = (0, 0), r = 10

x^{2} + y^{2} + 12 x + 5 y + 7 = 0

x^{2} + y^{2} + 8 x - 20 = 0

(x + 9)^{2} + (y - 2)^{2} = 169

(x + 5)^{2} + (y - 7)^{2} = 11

x^{2} + y^{2} - 14 x + 8 y + 64 = 0

What is x^2+y^2=sqrt(10) ?
The solution to x^2+y^2=sqrt(10) is Circle with (a,b)=(0,0),r=sqrt(\sqrt{10)}