What is (x+9)^2+(y-2)^2=169 ?

The solution to (x+9)^2+(y-2)^2=169 is Circle with (a,b)=(-9,2),r=13

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(x+9)^2+(y-2)^2=169

(x + 9)^{2} + (y - 2)^{2} = 169

(a, b) = (- 9, 2), r = 13

Solution steps

(x + 9)^{2} + (y - 2)^{2} = 169

Rewrite

(x + 9)^{2} + (y - 2)^{2} = 169

in the form of the standard circle equation

(x - (- 9))^{2} + (y - 2)^{2} = 1 3^{2}

Therefore the circle properties are:

(a, b) = (- 9, 2), r = 13

(x + 5)^{2} + (y - 7)^{2} = 11

x^{2} + y^{2} - 14 x + 8 y + 64 = 0

a^{2} + b^{2} = 165.1

x^{2} + y^{2} - 2 x - 8 y = - 13

16 = (x)^{2} + (y)^{2}

What is (x+9)^2+(y-2)^2=169 ?
The solution to (x+9)^2+(y-2)^2=169 is Circle with (a,b)=(-9,2),r=13