What is x^2+y^2+12x+5y+7=0 ?

The solution to x^2+y^2+12x+5y+7=0 is Circle with (a,b)=(-6,-5/2),r=(sqrt(141))/2

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x^2+y^2+12x+5y+7=0

x^{2} + y^{2} + 12 x + 5 y + 7 = 0

(a, b) = (- 6, - \frac{5}{2}), r = \frac{141}{2}

Solution steps

x^{2} + y^{2} + 12 x + 5 y + 7 = 0

Rewrite

x^{2} + y^{2} + 12 x + 5 y + 7 = 0

in the form of the standard circle equation

(x - (- 6))^{2} + (y - (- \frac{5}{2}))^{2} = (\frac{141}{2})^{2}

Therefore the circle properties are:

(a, b) = (- 6, - \frac{5}{2}), r = \frac{141}{2}

x^{2} + y^{2} + 8 x - 20 = 0

(x + 9)^{2} + (y - 2)^{2} = 169

(x + 5)^{2} + (y - 7)^{2} = 11

x^{2} + y^{2} - 14 x + 8 y + 64 = 0

a^{2} + b^{2} = 165.1

What is x^2+y^2+12x+5y+7=0 ?
The solution to x^2+y^2+12x+5y+7=0 is Circle with (a,b)=(-6,-5/2),r=(sqrt(141))/2