What is (x+3)^2+(y-6)^2=49 ?

The solution to (x+3)^2+(y-6)^2=49 is Circle with (a,b)=(-3,6),r=7

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(x+3)^2+(y-6)^2=49

(x + 3)^{2} + (y - 6)^{2} = 49

(a, b) = (- 3, 6), r = 7

Solution steps

(x + 3)^{2} + (y - 6)^{2} = 49

Rewrite

(x + 3)^{2} + (y - 6)^{2} = 49

in the form of the standard circle equation

(x - (- 3))^{2} + (y - 6)^{2} = 7^{2}

Therefore the circle properties are:

(a, b) = (- 3, 6), r = 7

6 4^{2} = a^{2} + b^{2}

4 x^{2} + 4 x + 4 y^{2} - 16 y = 19

x^{2} + y^{2} = 11

x^{2} + (y - 3)^{2} + 4 x = 25

x^{2} - 2 y + y^{2} + 3 x + 2 = 0

What is (x+3)^2+(y-6)^2=49 ?
The solution to (x+3)^2+(y-6)^2=49 is Circle with (a,b)=(-3,6),r=7