What is 3y^2+3x^2-27=0 ?

The solution to 3y^2+3x^2-27=0 is Circle with (a,b)=(0,0),r=3

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3y^2+3x^2-27=0

3 y^{2} + 3 x^{2} - 27 = 0

(a, b) = (0, 0), r = 3

Solution steps

3 y^{2} + 3 x^{2} - 27 = 0

Rewrite

3 y^{2} + 3 x^{2} - 27 = 0

in the form of the standard circle equation

(x - 0)^{2} + (y - 0)^{2} = 3^{2}

Therefore the circle properties are:

(a, b) = (0, 0), r = 3

9 x^{2} - 36 x + 9 y^{2} + 6 y = - 28

x^{2} + y^{2} - 2 x - 16 y + 29 = 0

(x - 3)^{2} + (y - 8)^{2} = 25

(x - 0)^{2} + (y - 0)^{2} = 36

(x + 0)^{2} + (y + 0)^{2} = 6

What is 3y^2+3x^2-27=0 ?
The solution to 3y^2+3x^2-27=0 is Circle with (a,b)=(0,0),r=3