What is (x-3)^2+(y-8)^2=25 ?

The solution to (x-3)^2+(y-8)^2=25 is Circle with (a,b)=(3,8),r=5

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(x-3)^2+(y-8)^2=25

(x - 3)^{2} + (y - 8)^{2} = 25

(a, b) = (3, 8), r = 5

Solution steps

(x - 3)^{2} + (y - 8)^{2} = 25

Rewrite

(x - 3)^{2} + (y - 8)^{2} = 25

in the form of the standard circle equation

(x - 3)^{2} + (y - 8)^{2} = 5^{2}

Therefore the circle properties are:

(a, b) = (3, 8), r = 5

(x - 0)^{2} + (y - 0)^{2} = 36

(x + 0)^{2} + (y + 0)^{2} = 6

(x + 2)^{2} + (y - 2)^{2} = 16

(x + 5)^{2} + (y - 2)^{2} = 61

(x + 2)^{2} + (y + \frac{1}{2})^{2} = \frac{17}{4}

What is (x-3)^2+(y-8)^2=25 ?
The solution to (x-3)^2+(y-8)^2=25 is Circle with (a,b)=(3,8),r=5