What is x^2-8x+y^2-4y=29 ?

The solution to x^2-8x+y^2-4y=29 is Circle with (a,b)=(4,2),r=7

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x^2-8x+y^2-4y=29

x^{2} - 8 x + y^{2} - 4 y = 29

(a, b) = (4, 2), r = 7

Solution steps

x^{2} - 8 x + y^{2} - 4 y = 29

Rewrite

x^{2} - 8 x + y^{2} - 4 y = 29

in the form of the standard circle equation

(x - 4)^{2} + (y - 2)^{2} = 7^{2}

Therefore the circle properties are:

(a, b) = (4, 2), r = 7

(x + 11)^{2} + (y + 6)^{2} = 324

(x + 3)^{2} + (y - 2)^{2} = 1^{2}

(x - 1)^{2} + (y)^{2} = 1

x^{2} - 8 x + y^{2} + 12 y = - 43

x^{2} + y^{2} - 10 x + 26 y + 167 = 0

What is x^2-8x+y^2-4y=29 ?
The solution to x^2-8x+y^2-4y=29 is Circle with (a,b)=(4,2),r=7