What is (x-1)^2+(y)^2=1 ?

The solution to (x-1)^2+(y)^2=1 is Circle with (a,b)=(1,0),r=1

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(x-1)^2+(y)^2=1

(x - 1)^{2} + (y)^{2} = 1

(a, b) = (1, 0), r = 1

Solution steps

(x - 1)^{2} + y^{2} = 1

Rewrite

(x - 1)^{2} + y^{2} = 1

in the form of the standard circle equation

(x - 1)^{2} + (y - 0)^{2} = 1^{2}

Therefore the circle properties are:

(a, b) = (1, 0), r = 1

x^{2} - 8 x + y^{2} + 12 y = - 43

x^{2} + y^{2} - 10 x + 26 y + 167 = 0

(x + 4)^{2} + (y + 1)^{2} = 9

x^{2} + 2 x + 1 + y^{2} - 8 y + 16 = - 16 + 1 + 16

3 x^{2} + 3 y^{2} - 3 x - 3 y - 9 = 0

What is (x-1)^2+(y)^2=1 ?
The solution to (x-1)^2+(y)^2=1 is Circle with (a,b)=(1,0),r=1