What is 9-2x^2-2y^2=0 ?

The solution to 9-2x^2-2y^2=0 is Circle with (a,b)=(0,0),r= 3/(sqrt(2))

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9-2x^2-2y^2=0

9 - 2 x^{2} - 2 y^{2} = 0

(a, b) = (0, 0), r = \frac{3}{2}

Solution steps

9 - 2 x^{2} - 2 y^{2} = 0

Rewrite

9 - 2 x^{2} - 2 y^{2} = 0

in the form of the standard circle equation

(x - 0)^{2} + (y - 0)^{2} = (\frac{3}{2})^{2}

Therefore the circle properties are:

(a, b) = (0, 0), r = \frac{3}{2}

(x - 3)^{2} + (y - 2)^{2} = 1

x^{2} + y^{2} - 4 x + 4 y - 8 = 0

x^{2} + 10 x + y^{2} - 8 y = - 16

9 x^{2} + 9 y^{2} + 12 x + 36 y = 104

x^{2} + y^{2} + 4 x - 4 y - 2 = 0

What is 9-2x^2-2y^2=0 ?
The solution to 9-2x^2-2y^2=0 is Circle with (a,b)=(0,0),r= 3/(sqrt(2))