What is (9x-3)^2+(9y+12)^2=172 ?

The solution to (9x-3)^2+(9y+12)^2=172 is Circle with (a,b)=(1/3 ,-4/3),r=(2sqrt(43))/9

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(9x-3)^2+(9y+12)^2=172

(9 x - 3)^{2} + (9 y + 12)^{2} = 172

(a, b) = (\frac{1}{3}, - \frac{4}{3}), r = \frac{2 43}{9}

Solution steps

(9 x - 3)^{2} + (9 y + 12)^{2} = 172

Rewrite

(9 x - 3)^{2} + (9 y + 12)^{2} = 172

in the form of the standard circle equation

(x - \frac{1}{3})^{2} + (y - (- \frac{4}{3}))^{2} = (\frac{2 43}{9})^{2}

Therefore the circle properties are:

(a, b) = (\frac{1}{3}, - \frac{4}{3}), r = \frac{2 43}{9}

4 x^{2} + 4 y^{2} - 0^{2} = 4

x^{2} + y^{2} - 6 x - 8 y - 50 = 0

x^{2} + y^{2} - 2 x - 2 y - 11 = 0

y^{2} + (x + 1)^{2} = 4

(x + 2)^{2} + (y + 4)^{2} = 25

What is (9x-3)^2+(9y+12)^2=172 ?
The solution to (9x-3)^2+(9y+12)^2=172 is Circle with (a,b)=(1/3 ,-4/3),r=(2sqrt(43))/9