What is (x-3.5)^2+(y-3)^2<4.1 ?

The solution to (x-3.5)^2+(y-3)^2<4.1 is Circle with (a,b)=(3.5,3),r=2.02484…

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(x-3.5)^2+(y-3)^2<4.1

(x - 3.5)^{2} + (y - 3)^{2} < 4.1

(a, b) = (3.5, 3), r = 2.02484 \dots

Solution steps

(x - 3.5)^{2} + (y - 3)^{2} < 4.1

Rewrite

(x - 3.5)^{2} + (y - 3)^{2} < 4.1

in the form of the standard circle equation

(x - 3.5)^{2} + (y - 3)^{2} = 2.02484 \dots^{2}

Therefore the circle properties are:

(a, b) = (3.5, 3), r = 2.02484 \dots

x^{2} + (y + 14)^{2} = 25

x^{2} + y^{2} - 12 x + 12 y + 36 = 0

(x - 7)^{2} + (y + 2)^{2} = 16

x^{2} + y^{2} - 2 x + 8 y + 13 = 0

(x + 7)^{2} + (y + 8)^{2} = \frac{4}{9}

What is (x-3.5)^2+(y-3)^2<4.1 ?
The solution to (x-3.5)^2+(y-3)^2<4.1 is Circle with (a,b)=(3.5,3),r=2.02484…